Do you mean y=x^2.5? I you had y=13^2.77, it's easier to use log.
log y=2.77*log13 ~ 3.0856. 1217.9 is the antilog and answer.x=1217.9
But math can be more complicated. How about y^2.5=x^1.8. Logs really shine here. Take log of both sides. 2.5*log y = 1.8 log x. Say x=100 and 1.8 log 100 = 1.8*2=3.6. We have 2.5 log y = 3.6 and log y = 3.6/2.5 = 1.44. Now y = antilog 1.44=27.54229. So does 27.54229^2.5 = 100^1.8 ? Yes it does.
You multiply one or both equations by some constant (especially chosen for the next step), and add the two resulting equations together. Here is an example: (1) 5x + 2y = 7 (2) 2x + y = 3 Multiply equation (2) by -2; this factor was chosen to eliminate "y" from the resulting equations: (1) 5x + 2y = 7 (2) -2x -2y = -6 Add the two equations together: 3x = 1 Solve this for "x", then replace the result in any of the two original equations to solve for "y".
Algebraic equations with two variables will need two equations to be able to solve it. Then, you can solve it with either substitution, adding/subtracting them together, or graphing! Those are the basic steps... For example: An instance of substitution: 2x + 1 = y + 2 x + y = 3 You could isolate y in the second equation to equal y = 3-x. Then in the first equation, substitute y with what it equals to 2x + 1 = 3-x+2 Then you can solve for x!
You solve one of the equation for one of the variables. For example, if the variables involved are "x" and "y", you might solve for "y". It doesn't really matter what variable you solve for first, so you can solve for whatever variable is easiest to solve. Then - assuming you got, for example, "y = 3x -1", in this example you would replace every "y" by "3x - 1" in the other equation or equations.
just use the PEMDAS system. p-parenthesis e-exponents m-multiplication d-division a-adding s-subtracting
If: x+y = 8 and 2x-y = 5 Then by adding the equations together: 3x = 13 or x = 13/3 By substitution into the original equations: x = 13/3 and y = 11/3
one million as a power of ten
If you already know that x = -3 and y = 5 what linear equations are you wanting to solve?
You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".
The basic idea here is to look at both equations and solve for either x or y in one of the equations. Then plug the known value into the second equation and solve for the other variable.
Follow PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction), but do what is in the brackets first.
4
Equations can have as many variables as you want, however to solve an equation you need as many equations as there are unknowns. E.g. in an equation with x & y as the unknowns you would need two different equations containing x and/or y to solve them
y=2x+12 7x+y=24 (as there is y in both equations you can assume that the equations are equal to each other, so substitute) 7x+2x+12=30 (solve) 9x=18 x=2 (substitute into the first equation to solve for y) y=(2x2)+12 y=16
you use PEMDAS which is parentheses exponents multiplication and division from left to right addition and subtraction from left to right
Change f(x) to y and solve the problem.
Simultaneous equations are where you have multiple equations, often coupled with multiple variables. An example would be x+y=2, x-y=2. To solve for x and y, both equations would have to be used simultaneously.
You need two independent linear equations to solve for two unknown variables.