You have to put both variables on one side. If the question was 6x-2=x+13 then you would need to subtract the x from the side after the equals sign, and if you do something to one side to do the other. so now your question is 5x-2=13, which is a regular two step equation. just add 2 to each side, then divide 5. x should equal 3 in this example problem.
First, get the radical by itself. Then, square both sides of the equation. Then just solve the rest.
I assume that you mean that you are given a differential equation dy/dx and want to solve it. If that is the case, then you would multiply by dx on both sides and then integrate both the left and right sides of the equation.
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Yes you can, if the solution or solutions is/are real. -- Draw the graphs of both equations on the same coordinate space on the same piece of graph paper. -- Any point that's on both graphs, i.e. where they cross, is a solution of the system of equations. -- If both equations are linear, then there can't be more than one such point.
First, get the radical by itself. Then, square both sides of the equation. Then just solve the rest.
A calculator can be used to proportions to answer a equation. This is easier to solve when having variables on both sides.
You solve equations with fractions the same way you solve other equations. You perform various arithmetic operations on both sides of the equals sign until you get the result you want.
Your question lacks precision in its expression, but basically you divide the both sides by the coefficient of the unknown. Example: solve 3x = 15. Divide both sides by 3 to get x = 5.
Assuming you want to get rid of the fractions, you can multiply both sides of the equations by the greatest common factor of the fractions. Then you can solve the equation normally.
I assume that you mean that you are given a differential equation dy/dx and want to solve it. If that is the case, then you would multiply by dx on both sides and then integrate both the left and right sides of the equation.
You would solve them in exactly the same way as you would solve linear equations with real coefficients. Whether you use substitution or elimination for pairs of equations, or matrix algebra for systems of equations depends on your requirements. But the methods remain the same.
you apply the Laplace transform on both sides of both equations. You will then get a sytem of algebraic equations which you can solve them simultaneously by purely algebraic methods. Then take the inverse Laplace transform .
Just divide both sides by 7...
4x + 5 = 13. To solve algebraic equations, you need to get the variable by itself on one side of the equation. Start by subtracting 5 from both sides >>> 4x = 8. Then divide both sides by 4 to find what 'x' equals >>> x = 2.
First, add 19 on both sides. You end up with 2s = 48. Then divide both sides by 2 in order to isolate the 's'. You get s = 24.
You do operations to get them all on one side. Eg 5x = 7y, you would divide both sides by (y) and end up with 5x/y = 7