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How do you solve for y if the system of equations x y 4 and 2x 2y 8?
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∙ 11y ago
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∙ 11y ago
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Solve for y in the following system of equations-2x - 2y equals -12?
To solve an equation with two unknowns (x and y), you need two independent equations. answer -2x-2y=-12 -2(3)-2(3)=-12 -6-6+-12 so x=3, y=3
Solve the following system of equations using sustitution x6y-4 x-2y 28?
To solve a system of equations, you need equations (number phrases with equal signs).
How do you solve linear equations by using elimination?
You multiply one or both equations by some constant (especially chosen for the next step), and add the two resulting equations together. Here is an example: (1) 5x + 2y = 7 (2) 2x + y = 3 Multiply equation (2) by -2; this factor was chosen to eliminate "y" from the resulting equations: (1) 5x + 2y = 7 (2) -2x -2y = -6 Add the two equations together: 3x = 1 Solve this for "x", then replace the result in any of the two original equations to solve for "y".
Solve the following system of equations express your answer as an ordered pair 2x plus 5y equals 16 and -5x minus 2y equals 2?
The solutions are: x = -2 and y = 4
Does this system of equations have one solution no solutions or an infinite number of solutions 2x plus y equals 5 and 2y plus x equals 4?
One solution 2x+y =5 x+2y=4 multiply 1st eq by 2 rhen subtract: 4x+2y = 10 x + 2y = 4 3x = 6 x = 2 plug x into any of the above two equations and solve y = 1
What is X - 2y equals -4 and 2x - y equals 1?
x - 2y = -4 2x - y = 1 To solve this system of equations, I used matrices, and got x = 2 and y = 3.
Solve for y in the following system of equations-2x - 2y equals -12?
To solve an equation with two unknowns (x and y), you need two independent equations. answer -2x-2y=-12 -2(3)-2(3)=-12 -6-6+-12 so x=3, y=3
Solve this system of equations by addition in the space . Then indicate the first of three steps which must be used in the procedure.?
Solve this system of equations by addition in the space provided. Then indicate the first of three steps which must be used in the procedure. y = x - 4 and 2x + 2y = 4 a. x - y = 4 2x + 2y = 4 b. 2(x - 4) + 2y = 4 c. y = x - 4 2x + 2y = 4 d. 2x + 2(x - 4) = 4 e. y = -x + 4 Save Answer
How do you solve systems of equations using substitution?
3(5x-2y)=18 5/2x-y=-1
Use the substitution method to solve the system of equations. Choose the correct ordered pair. 2y plus 2x 20 y - 2x 4?
It is not possible to know exactly what the question is because the browser used by this site is almost totally useless for mathematical questions: it rejects most symbols. If the equations are 2y + 2x = 20 and y - 2x = 4,then the solution is (2, 8).
Solve the following system of equations using sustitution x6y-4 x-2y 28?
To solve a system of equations, you need equations (number phrases with equal signs).
How do you solve 2x plus 2y equals 4 and 4x plus y equals 1?
2x + 2y = 44x + y = 1There are many methods you can use to solve this system of equations (graphing, elimination, substitution, matrices)...but no matter what method you use, you should get x = -1/3 and y = 7/3.
How do you solve linear equations by using elimination?
You multiply one or both equations by some constant (especially chosen for the next step), and add the two resulting equations together. Here is an example: (1) 5x + 2y = 7 (2) 2x + y = 3 Multiply equation (2) by -2; this factor was chosen to eliminate "y" from the resulting equations: (1) 5x + 2y = 7 (2) -2x -2y = -6 Add the two equations together: 3x = 1 Solve this for "x", then replace the result in any of the two original equations to solve for "y".
What is the value of x and y in this equation 2x plus 3y equals -5 and 5x plus 2y equals 4 The number for x and y stay the same for both parts of the equation?
This is a system of equations, and we can use various methods to solve it. We'll use substitution in this case. We're told: 2x + 3y = -5 5x + 2y = 4 To solve by substitution, what we need to do is take either one of those equations, and solve it for either x or y. Let's take the second one and solve it for x: 5x + 2y = 4 5x = 4 - 2y x = (4 - 2y)/5 Now we can take that solution for x, and substitute it into the other equation: 2x + 3y = -5 2((4 - 2y)/5) + 3y = -5 (8 - 4y) / 5 + 3y = -5 (8 - 4y + 15y) / 5 = -5 8 - 4y + 15y = -25 11y = -33 y = -3 We now have a value for y, and can plug it into either of the original equations to solve for x: 2x + 3y = -5 2x + 3(-3) = -5 2x - 9 = -5 2x = 4 x = 2 To verify our answer, we can plug either x or y into the other of our original equations, and see if we get the same result for the other variable: 5x + 2y = 4 5(2) + 2y = 4 10 + 2y = 4 2y = -6 y = -3 So that confirms our answer, and the two equations intersect at the point (2, -3).
Solve the following system of equations express your answer as an ordered pair 2x plus 5y equals 16 and -5x minus 2y equals 2?
The solutions are: x = -2 and y = 4
Does this system of equations have one solution no solutions or an infinite number of solutions 2x plus y equals 5 and 2y plus x equals 4?
One solution 2x+y =5 x+2y=4 multiply 1st eq by 2 rhen subtract: 4x+2y = 10 x + 2y = 4 3x = 6 x = 2 plug x into any of the above two equations and solve y = 1
How do you solve 2x-2y equals 1?
get it to y= -2y = 1 - 2x y = x - 0.5
