Typically in these math questions you will have two equations.
Both equations will have, lets say an x and y value. Two unknown variables.
Take the first equation and rearrange it so that you isolate one of the variables, lets say x.
To isolate x, arrange the equations so that x is on one side, and every other number is on the other.
This expression is equal to x.
Take this expression (all the numbers on opposite side of the side where the x is), and plug it into the second equation. That it, where ever the x appears in the second equation, replace it with this expression.
Solve for y through simple algebra.
Now, take the y value you solved for and plug it into one of the original equations. That is, replace the y in the equation with this number. Solve for x through algebra.
The x and y values you receive are known as the solution.
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Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1
You solve this by theoretically diverting the hypotenuse of the x divided by the overall beneficial procedure of y
(2,3)
X = 135 and y = 15 Solved by addition and substitution
When you have a system of equations and you can solve for one in terms of th others and then replace it in the other equations that is substitution. x+y=15 x-y=1 well the second one can be x=1+y x+y=15 then can be (1+y)+y=15 by substitution. 1+2y=15 2y=14 y=7 Then x+7=15 x=8