2x²-x=0.5 is more manageable in the standard quadratic form : 2x2 - x - 0.5 = 0
double this to get rid of that pesky 0.5 : 4x2 - 2x -1 = 0
The quadratic formula solves ax2 + bx + c =0 using x = (-b +/- (b2-4ac) 0.5 ) / 2a
x equals [minus b plus or minus (square root of {b squared minus 4ac})] all over 2a
putting in a=4, b=-2, c=-1 gives (2 +/- (4 + 16)0.5 ) / 8
which reduces to( 1 +/- (5)0.5) / 4
this evaluates to x= .809 or -.309
Notice that plus or minus square root (b2 - 4ac) usually produces two different solutions. Equations in the second degree always have two solutions; if the quadratic is such that b2 equals 4ac the formula seems to give only one solution. Don't worry about this; there are still two solutions, they just happen to be identical!
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i = sqrt of (-1) ( imaginary) i squared = sqrt(-1) x sqrt (-1) = -1 (minus one)
one squared equals one.
-1 multiplied by -1 is 1
3c(squared)-17c-6 = 0 (3c+1)(c-6) = 0 c= negative one third or positive 6
poo you