There are at least two algebraic ways. The simple way is to put x = 0 and solve:
Thus: -6*0 -9y = -3
that is -9y = -3 or 9y = 3 so that y = 1/3
Rewrite the equation in slope-intercept form (y = mx + c).
Thus: -9y = 6x - 3
So that y = -2/3*x + 1/3 and so c = intercept 1/3
The non-algebraic way is to draw the graph and read off the value of the intercept.
The y-intercept of a linear equation is the point on the y-axis at which the line cuts.It could be found by plugging x = 0 in the given linear equation.For example,Consider 3x + 2y = 6. To find the y-intercept just plug x = 0 in the equation.3(0) + 2y = 62y = 6y = 3(0, 3) is the y-intercept of the linear equation 2x + 3y = 6.Note:In the same way we can find the x-intercept by plugging y = 0 in the given linear equation.
At the x-intercept on the graph of the equation, y=0. Take the equation, set 'y' equal to zero, and solve the equation for 'x'. The number you get is the x-intercept.
First write it in the "slope-intercept" form : y = mx + c Then the y-intercept is (0, c)
The y-intercept is c in the standard form. The x-intercept is -c/m.
With great difficulty because without an equality sign the given terms can't be considered to be an equation but if you mean y = 14.2-3.9x then the y intercept is 14.2
The y-intercept of a linear equation is the point on the y-axis at which the line cuts.It could be found by plugging x = 0 in the given linear equation.For example,Consider 3x + 2y = 6. To find the y-intercept just plug x = 0 in the equation.3(0) + 2y = 62y = 6y = 3(0, 3) is the y-intercept of the linear equation 2x + 3y = 6.Note:In the same way we can find the x-intercept by plugging y = 0 in the given linear equation.
-4y=-5x+18 is the same equation. Now divide both sides by -4 and you find the y intercept is -18/4 or -9/2
At the x-intercept on the graph of the equation, y=0. Take the equation, set 'y' equal to zero, and solve the equation for 'x'. The number you get is the x-intercept.
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The x-intercept is where the line intersects with, or crosses, the x axis. To find it, take the equation, put in 0 for y, and solve for x. The intercept will be (#,0).
At a y-intercept, the graph touches the y-axis, meaning the value of x is 0. So, in any linear equation, simply set x equal to 0 and solve for y. In the slope-intercept form of a linear equation (y = mx + b), the y-intercept value is represented by the variable b.
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plug in a 0 for the "x" value of the equation, and solve it :D
If necessary, rearrange the linear equation so that it is in the slope-intercept form: y = mx + c Then the gradient of the line is m.
5x - 10 = -20This equation can be restated as 5x = -10 : x = -2This is the equation of a straight line perpendicular to the x axis and passing through the point x = -2. There is no y intercept and the slope is indeterminate.
First write it in the "slope-intercept" form : y = mx + c Then the y-intercept is (0, c)
The y-intercept is c in the standard form. The x-intercept is -c/m.