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There are at least two algebraic ways. The simple way is to put x = 0 and solve:
Thus: -6*0 -9y = -3
that is -9y = -3 or 9y = 3 so that y = 1/3
Rewrite the equation in slope-intercept form (y = mx + c).
Thus: -9y = 6x - 3
So that y = -2/3*x + 1/3 and so c = intercept 1/3
The non-algebraic way is to draw the graph and read off the value of the intercept.
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How do you find the y-intercept of a linear relationship from an equation?
The y-intercept of a linear equation is the point on the y-axis at which the line cuts.It could be found by plugging x = 0 in the given linear equation.For example,Consider 3x + 2y = 6. To find the y-intercept just plug x = 0 in the equation.3(0) + 2y = 62y = 6y = 3(0, 3) is the y-intercept of the linear equation 2x + 3y = 6.Note:In the same way we can find the x-intercept by plugging y = 0 in the given linear equation.
How do you find the x intercept on a linear equation?
At the x-intercept on the graph of the equation, y=0. Take the equation, set 'y' equal to zero, and solve the equation for 'x'. The number you get is the x-intercept.
How do you find the y-intercept of a linear equation?
First write it in the "slope-intercept" form : y = mx + c Then the y-intercept is (0, c)
How do you find the x and y intercepts of a linear equation in standard form?
The y-intercept is c in the standard form. The x-intercept is -c/m.
How do you find the y intercept of the linear regression equation y14.2-3.9x?
With great difficulty because without an equality sign the given terms can't be considered to be an equation but if you mean y = 14.2-3.9x then the y intercept is 14.2
