2.5 years
90 per cent of its initial value.
i will give you a very smart trick to find the ten percent of any number in just 2 seconds. See , 10 % 0f 500 = 50.0 10 % of 3500 = 350.0 you have to put a decimal just after the unit digit's place and you are done, So for 10 % 0f 110,000 = 11000.0
The factors of 3500 are 1, 2, 4, 5, 7, 10, 14, 20, 25, 28, 35, 50, 70, 100, 125, 140, 175, 250, 350, 500, 700, 875, 1750, and 3500. The prime factors of 3500 are 2 x 2 x 5 x 5 x 5 x 7.
Oh, dude, like, 3500 times 12 is 42,000. It's like, you just gotta multiply 3500 by 12, and boom, there's your answer. Math, man, it's wild.
3500
4408.992
Interest =0.09/365*270*3500 = $233.01 (approximate, depends on composite or accumulation terms) Total = $3,500.00 + 233.01 = $3,733.01 (approximate)
The answer: $1,000 was invested at %5. $2,500 was invested @ 8% It is done with a system of equations when "x" is a portion of $3,500 and "y" is a portion of $3,500: x + y = 3500AND .05x +.08y = 250 Use algebra and solve #2 for "x" as follows: .05x + .08y = 250 .05x = 250 - .08y x = 5000 - 1.6y plug the value of "x" into the first equation and solve for "y": 5000 - 1.6y + y = 3500 5000 - 3500 - 1.6y + y = 0 1500 - 1.6y + y = 0 1500 = 1.6y -y 1500 = .6y 2500 = y plug the value of "y" into the original equation and solve for "x" x + 2500 = 3500 x = 3500 - 2500 x = 1000 You can plug them both into the 2nd equation in the system to check it.
16 percent of 3500 is 560.
Under normal commercial practice. use compound interest / I(n) = I(o)[ 1 + r/100]^(n) Hene I(10) = 3500[1 + 6/100]^(10) I(10) = 3500[ 1.06^(10)) I(10) = 3500 *1.790847697 I(10) = 6267.966938 I(10) ~ 6267.97 Amount of interest paid is 6267.07 = 3500 = 2767.97 is the amount of interest paid .
13% of 3500= 13% * 3500= 0.13 * 3500= 455
6.25% of 3500= 6.25% * 3500= 0.0625 * 3500= 218.75
15% of 3500 = 15% * 3500 = 0.15 * 3500 = 525
50% of $3500 = 50% * 3500 = 0.5 * 3500 = $1750
He pays $696.50 interest.
It is 3500%.
3500 is 70% of 5000.