123
There are 3 values (1, 2, 3) for each of the 4 digits. Therefore, there are 3*3*3*3 or 81 four digit numbers that can be formed.
Just think of how many possibilities you have for each digit. 10x9x8x7x6x5x4x3x2 or 10 factorial is 3 628 800.
You can make six different combinations: 123 132 213 231 321 312. If you just need to know the number of combinations, you could find the answer without writing everything out by letting x represent the number of digits and calculating x*(x-1).
If you can repeat a digit, there are 27. If you can't repeat a digit, there are only 6.
Just 6: 123 132 213 231 312 321
321 312 213 231 123 132 6 3 digit numbers.
123
123
There are 3 values (1, 2, 3) for each of the 4 digits. Therefore, there are 3*3*3*3 or 81 four digit numbers that can be formed.
1 as in 100 2 as in 20 3 as in 3
There are 15180 combinations.
1+2+3=6 1x2x3=6 123
Six. 321 312 231 213 123 132
123 132 231 213 321 312 : 6 [if no repeated digits]. If repetition is allowed [such as 111, or 223], then there are 27 possibilities.
Sure 123 932 910 the sum is 1965
9876 - 123= 9753