There are 26 different letters that can be chosen for each letter. There are 10 different numbers that can be chosen for each number. Since each of the numbers/digits that can be chosen for each of the six "spots" are independent events, we can multiply these combinations using the multiplicative rule of probability.
combinations = (# of different digits) * (# of different digits) * (# of different digits) * (# of different letters) * (# of different letters) * (# of different letters) = 10 * 10 * 10 * 26 * 26 * 26 = 103 * 263 = 1000 * 17576 = 17,576,000 different combinations.
With 4 digits you can have 24 = 16 combinations. 1 combination with 0 digits; 4 combinations with 1 digit: 1, 2, 4 and 8 6 combinations with 2 digits: 12, 14, 18, 24, 28 and 48 4 combinations with 3 digits: 124, 128, 148 and 248 1 combination with all 4 digits. In a combination the order of digits is not relevant so that 124 is the same as 142.
For every letter there are 26 possibilities, for every digit, 10. Multiply all of this together (26 x 26 x 10 x 10 x 10) = 676,000.
There are 167960 9 digits combinations between the numbers 1 and 20.
Number of possible groups of 3 letters = 26 x 25 x 24 = 15,600. For each of these . . .Number of possible groups of 3 digits = 9 x 9 x 8 = 648 .Total number of possible distinct plates = 15,600 x 648 = 10,108,800
You can get only four combinations: They are: 11, 118, 119 and 1189. In a combination, the order of the digits does not matter.
35,152,000 (assuming that 000 is a valid number, and that no letter combinations are disallowed for offensive connotations.) Also, no letters are disallowed because of possible confusion between letters and numbers eg 0 and O.
How many license plates can be made using either two uppercase English letters followed by four digits or two digits followed by four uppercase English letters?
(26) x (26) x (10,000) = 6,760,000
In most states, the number itself tells those who need to know what kind of license it is. In California, most cars and trucks have a digit, three letters and three more digits. A commercial truck plate has a letter followed by six digits, and there are other combinations for big trucks, trailers, and other categories.
If all letters and numbers are allowed, the possibilities are 26x26x10x10x10x10. So: 6760000 different plates.
it 26 to the power 4 and then 99 for the numbers figure that out add the two together
Any three letters, in any order, including repeated letters gives 263 combinations each of which could have one of 9 digits so 26 x 26 x 26 x 9 ie 158184 different plates.
There are 26 possible letters and 10 possible numbers. The number of license plates possible is then 26*26*10*10*10*10 = 6760000.
12
There are different numbers of combinations for groups of different sizes out of 9: 1 combination of 9 digits 9 combinations of 1 digit and of 8 digits 36 combinations of 2 digits and of 7 digits 84 combinations of 3 digits and of 6 digits 126 combinations of 4 digits and of 5 digits 255 combinations in all.
You can make: 1 combination containing 0 digits, 7 combinations containing 1 digits, 21 combinations containing 2 digits, 35 combinations containing 3 digits, 35 combinations containing 4 digits, 21 combinations containing 5 digits, 7 combinations containing 6 digits, and 1 combinations containing 7 digits. That makes 2^7 = 128 in all.
An infinite number. You did not constrain your scenario to have no repeating patterns. Would you care to try again? If you want unique combinations: (262 + 263) * (92 + 93) = 14,784,120