First, we want to find the first multiple of 7 above 100. This is 105. 105/7=15.
Next, we want to find the last multiple of 7 below 500. That would be 497/7=71.
Now, we perform 71-15=56. Since our list was inclusive, meaning that we counted both 105 and 497, we add one to get 57 multiples of 7 between 100 and 500.
100, 200, 300, 400, 500, 600, 700, 800, 900, 1000
7 x 29 = 203, 7 x 71 = 497. There are therefore 71 - 28 ie 43 multiples of 7 in the range.
The 3 digit numbers under 500 are 100 through 499.
Between 100 annnd 500 dollars.
Accuracy % = ((keystrokes - errors) / keystrokes) * 100 Example: 500 keystrokes - 25 errors = 475 accurate keystrokes 95% = ((500 - 25) / 500) * 100 = (475 / 500) * 100) = .95 * 100 Check: 500 keystrokes - 25 errors = 475 accurate keystrokes 500 keystrokes * 95% accuracy = 500 * .95 = 475 accurate keystrokes 475=475=true! --------------------------- Original Poster's Method: --------------------------- number of mistakes divided by the number of keystrokes multiply by 100 subtract from 100
There are 67.
There are 166 multiples in 500 (500/3=166r2)and 33 multiples in100(100/3=33 r1) if you subtract the later from the first.... 166-33=133
There are no multiples of 500 in 100.
There are 83 multiples of six that fall between 500 and 1,000.
There are 67 multiples of 6 and 50 multiples of 8 in that range. Their total, 117, will include numbers that are both.
43
the multiples of 25 between 1 and 500 are 25,50 ,75,100,125,150,175,200,225,250,275,300,325,350,375,400,425,450,475, & 500
Multiples of 100 are numbers into which 100 will go with no remainder. 100, 200, 300, 400, 500,.....5000, 6000, 7000, 8000,.... 8200 etc are multiples of 100. With this information you can work out your answer. 7800, 7900, 8000, 8100, 8200
500 contains 50 multiples of 10.
Multiples of 125 are 125, 250, 375, 500, etc. Multiples of 50 are 50, 100, 150, 200, 250, etc. Common multiples of 125 and 50 are 250, 500, 750, 100, etc.
100, 200, 300, 400, 500.
100, 200, 300, 400, 500.