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There are 30 multiples of 30 between 100 and 999.
999 999. 1 million and 2 million aren't counted. It is only the number inbetween. so from 1000001, 1000002,.........1999998, 1999999 which is 999 999 numbers
The Number of Elements in a ListIf m and n are integers and m ≤ n, then there are n − m + 1 integers from m to ninclusive.m = 100, n = 999according to theorem above999 - 100 + 1 = 900
999-111=888 888 3 digit numbers can be made with numbers between 1 - 9
The smallest such number is 100, the largest is 999, so the size of this set is:999 - 100 + 1 Another way to solve this: You have: * 9 options for the first digit * 10 options for the second digit * 10 options for the third digit Multiply all these numbers together.