The first answer given was 6 x 6 = 36. I think a better answer is 91. The grid contains not only 36 small squares, it contains 25 2x2 squares, 16 3x3 squares, etc., all the way up to one big 6x6 square. If you think this interpretation makes no sense, then consider the parallel question, 'How many rectangles are there in a 6 x 6 grid?'
There are 49 of the smallest squares. However, any grid forms "squares" that consist of more than one of the smallest squares. For example, there are four different 6x6 squares that each include 36 of the small squares, nine different 5x5 squares, sixteen 4x4 squares, twenty-five 3 x 3 squares, and thirty-six different squares that contain 4 of the small squares. One could therefore discern 140 distinct "squares." The number can be calculated from the formula [(n)(n+1)(2n+1)] / 6 where n is the grid size.
100
There are 5 squares in a 2 by 2 grid if the large square enclosing all four smaller squares is included in the count.
If they are 1 x 1 squares there would be 144 in a 12 x 12 grid.
depends on the size of the square
6x6 square would make 36 square units of space. Each 2x2 square would fit in a 4 square unit space. So therefore, you would need 9 2x2 squares to fill a 6x6 grid.
You really should do your own homework - this is a question designed to make you analyse number patterns and devise a method to predict the answer that can be applied to grids of differing size. If we start with a square cut into a 3x3 grid, we can count the nine single (1x1) squares in the grid, the one 3x3 square, and then four 2x2* squares, making a total of 14. Try it out, then work your way up to 6x6 (a 36 square grid) by way of 4x4 and 5x5, looking to see how the grid's dimensions correlate to the number of varying-sized squares that can be counted. As a tip- in a 6x6 grid, you will have one 6x6 square, thirty-six 1x1 squares, and how many 2x2, 3x3, 4x4, and 5x5 squares? *The squares can overlap, obviously.
There are many different sized squares on a chessboard. The smallest squares are in an 8x8 grid, so we have 64 small squares. There are 7x7 2x2 squares, so we have 49 2x2 squares There are 6x6 3x3 squares, so we have 36 3x3 squares There are 5x5 4x4 squares, so we have 25 4x4 squares There are 4x4 5x5 squares, so we have 16 5x5 squares There are 3x3 6x6 squares, so we have 9 6x6 squares There are 2x2 7x7 squares, so we have 4 7x7 squares And there's the one big square that's the chessboard. All this adds up to 204 squares.
441
196 full squares. If you can cut the 6x6 squares in thirds to fill the excess then it's 200 2/3.
The first answer given was 6 x 6 = 36. I think a better answer is 91. The grid contains not only 36 small squares, it contains 25 2x2 squares, 16 3x3 squares, etc., all the way up to one big 6x6 square. If you think this interpretation makes no sense, then consider the parallel question, 'How many rectangles are there in a 6 x 6 grid?'
4 squares in a 2 by 2 grid 9 squares in a 3 by 3 grid 16 squares in a 4 by 4 grid 25 squares in a 5 by 5 grid 36 squares in a 6 by 6 grid 49 squares in a 7by 7 grid 64 squares in a 8 by 8 grid 81 squares in a 9 by 9 grid 100 squares in a 10 by 10 grid
Actually, there is more than 81 squares. SQUARE SIZES Multiplication to do: 1x1=81 ---> 9x9 2x2=64 ---> 8x8 3x3=49 ---> 7x7 4x4=36 ---> 6x6 5x5=25 ---> 5x5 6x6=16 ---> 4x4 7x7=9 ---> 3x3 8x8=4 ---> 2x2 9x9=1 ---> 1x1 now add up all products or amount of squares for each size.....and you get? 285!!! there are 285 squares inn a 9x9 grid.
It is not possible to answer in terms of a grid that cannot be seen, but a normal grid of 2 squares x 2 squares will have 5 squares.
There are 49 of the smallest squares. However, any grid forms "squares" that consist of more than one of the smallest squares. For example, there are four different 6x6 squares that each include 36 of the small squares, nine different 5x5 squares, sixteen 4x4 squares, twenty-five 3 x 3 squares, and thirty-six different squares that contain 4 of the small squares. One could therefore discern 140 distinct "squares." The number can be calculated from the formula [(n)(n+1)(2n+1)] / 6 where n is the grid size.
The answer depends on the grid.