You can subtract 10 from 100 ten times before reaching zero. Each subtraction reduces the number by 10, so after ten subtractions, you will have 100 - (10 * 10) = 0. Therefore, you can subtract 10 from 100 ten times in total.
it's the number you get after you subtract the growth rate by a 100 i am not shire about it :)
First you subtract the new number from the original number then divide it by the original number and multiply that by 100 original-new __________*100 original
The number 7 occurs once. The digit 7 occurs 20 times.
111-11=100.. This way, you used the number 1 five times and reached the value of a 100.
To find the number that, when subtracted from 100, gives you 52, you would subtract 48 from 100. This is because 100 - 48 = 52. So, the number you are looking for is 48.
100
5 times
100
Riddle answer : As many as you like -- (100-10) will always equal 90. However, if it isn't a riddle, the answer would be 10 to reach 0. You could continue to subtract 10 an infinite number of times, yielding an increasing negative value.
You can subtract 5 from 100 a total of 20 times before you reach zero. Each subtraction decreases the total by 5, so after 20 subtractions, you would have 0 left. However, if you consider the question literally, you can subtract 5 from 100 as many times as you want, but the meaningful answer is that you can do it 20 times until you no longer have a positive number.
Once! After you have subtracted it once, you are subtracting 100 from 1900, and then 100 from 1800 and on and on
100 tiem if u subract it by one
just subtract 100 by 38 DUH!
So call the number you need "x" then you have 4x +16=100 so you subtract the 16 from 100 and divide by 4
How many time can you subtract2.5 from 30 until you get 0
There are infinitely many solutions for that. Choose ANY number as the first number. The subtract 100 minus this number, to get the second number.
Subtract a negative, eg 100 - (-1) = 101.