All I know is that each person can sit on a chair. There aren't many ways with the details you said. There might be 2 chairs with 2 people on each chair. There really only is one way.
(b) A tea party is arranged for 16 persons along two sides of a table with 8 chairs on each side. 4 persons wish to sit on on particular side and 2 on the other side. In how many ways can they be seated? (
7!(6*2*5*4*3*2*1)
There are 480 ways. The simplest way to get the answer is to find the total number of ways that they can sit and, from that, subtract the number in which A and B are next to one another. Total number of ways = 6! = 6*5*4*3*2*1 = 720. Now suppose A and B are next to one another. Treat AB as a single unit, and then the total number of ways is 5! = 5*4*3*2*1 = 120. But A and B can be next to one another in two ways: AB and BA. So, the total number of ways with A and B next to one another is 2*120 = 240. That leaves 720 - 240 = 480 ways in which the six can sit in a row with A and B not together.
hi i feel hot
128
555
8x7x6x5x4= 6720
5 chairs x 5 people = 25 choices
All I know is that each person can sit on a chair. There aren't many ways with the details you said. There might be 2 chairs with 2 people on each chair. There really only is one way.
Six.
Usually people sit on chairs. Some Synagogues may have benches to sit on.
chairs
Close to 150
There are about 2 sensible reasons. You get 25 chairs tell the 25 people to sit. Tell them to sit on the floor.Answer:25 people can be seated in 25! ways (25! is factorial 25, or 25x24x22x21 ....x3x2x1) as the first chair can be filled in 25 ways, the second in 24, the third in 23 and so on. This comes to 1.5511210043 × 1025 different ways
12
NO