The first-place finisher can be any one of the 9 skiers. For each of these choices, the second-place finisher can be any one of the remaining 8 skiers. For each of these choices, the third-place finisher can be any one of the remaining 7 skiers. So there are (9 x 8 x 7) = 504 ways in which the first, second, and third places can be comprised of members of the group of nine skiers.
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6840
hundredths
0.25 to the second decimal place.
120 ways, 5! (5 factorial) for first place you have 5 candidates, for second place you have 4 candidates, for third place you have 3 candidates, for fourth place you have 2 candidates, for last place you have 1 candidates, 5 x 4 x 3 x 2 x 1 = 120 different ways
The tenths place in decimals is the first digit to the right of the decimal point. For example, 15.2 is fifteen and two tenths.