Since each digit has 4 possibilities to be arranged, and 2 of the digits have the same value of 3, the number of arrangements would be 12.
4!/2! = 4 x 3 x 2!/2! = 12
4
you can arrange 8 pictures 28 different ways
3125 i think...There are 5 numbers.(It can be any five, say 9,7,6,2,1)To write them in different combinations you will do it in n! (factorial n) number of ways.n! = 5! = 5x4x3x2x1 = 120 different combinations.Even if the numbers were replaced by say A,B,C,D,E (or any 5 different letters or numbers) then it will still be 120 combinations for those 5 letters or numbers.
6
There are 12 ways to arrange 5 squares however i want to know what are the ways to do that! Can anybody help me too!!
3583 3538 3853 3835 3358 3385 5338 5383 5833 8335 8353 8533
One... numbers
24 ways
8! = 40320 ways.
Only one!
4
7!=5040
24
There are 6!/2! = 360 ways.
6 to the power of 6 so 6x6x6x6x6x6=46,656
120 if numbers can start with 0, otherwise, 96.
The numbers 1 through 6 can be arranged in a total of 6! (6 factorial) ways. This is calculated as 6 × 5 × 4 × 3 × 2 × 1, which equals 720. Therefore, there are 720 different ways to arrange the numbers 1 to 6.