Since each digit has 4 possibilities to be arranged, and 2 of the digits have the same value of 3, the number of arrangements would be 12.
4!/2! = 4 x 3 x 2!/2! = 12
4
you can arrange 8 pictures 28 different ways
6
There are 12 ways to arrange 5 squares however i want to know what are the ways to do that! Can anybody help me too!!
35,280
3583 3538 3853 3835 3358 3385 5338 5383 5833 8335 8353 8533
One... numbers
24 ways
8! = 40320 ways.
Only one!
4
7!=5040
24
There are 6!/2! = 360 ways.
120 if numbers can start with 0, otherwise, 96.
6 to the power of 6 so 6x6x6x6x6x6=46,656
-8