Answer is 19.
Explanation: we look at the entire range 99 to 131, in smaller groups.
99 has no digit 1.
100 to 109 have nine numbers with only one "1".
110 to 119 have no numbers with only one "1".
120 to 129 have nine numbers with only one "1".
130 has one number with only one "1".
131 does not have only one "1".
Total: 9 + 9 + 1 = 19
greatest two digit number is 99. smallest whole number is 0 there fore 99-0=99
Between 200 and 400 there are 18 whole numbers that contain the digit 7 once and only once: 207, 217, 227, 237, 247, 257, 267, 287, 297, 307, 317, 327, 337, 347, 357, 367, 387, and 397.
The smallest such number is 100, the largest is 999, so the size of this set is:999 - 100 + 1 Another way to solve this: You have: * 9 options for the first digit * 10 options for the second digit * 10 options for the third digit Multiply all these numbers together.
Factors are whole numbers that divide exactly into a whole number. These numbers have no remainder. Primes, on the other hand, have exactly two factors which are 1 and itself.
use the digit 1234to make two different numbers
18
138 of them.
18 of them.
The answer is 138
There are 195 such numbers.
There are 156 such numbers.
There are 175 such numbers.
greatest two digit number is 99. smallest whole number is 0 there fore 99-0=99
180
There are only 999 three digit whole numbers.
There is only one such number.
There are 900 three-digit whole numbers between 1 and 1000