Since one number is 3 times the other, I'd divide 84 by 4 and get 21. This is the lower number so the other must be 63.
The numbers are 21 and 63.
-- method -- We need X numbers which are consecutive, so the middle number will be 1/ X of the total. Divide the sum of the numbers by the number of numbers ... in this case divide 186 by 3. The numbers are to be consecutive and even, so subtract 2 from the number go get one of the numbers and add 2 to the number to get the other number. You now have three numbers which are even and consecutive. Now, place a minus sign in front of them, to turn them into negative numbers For instance 12, 14 and 16 are three consecutive numbers whose sum is 42. -12, -14 and - 16 are three consecutive even integers whose sum is -42 Now you know all you need to solve the problem.
the mean of four numbers is 25 and three of the numbers are 17 23 and 25 what is the fourth number?
So the problem is: Solve: 4x2 - x = 3
the sum of three numbers is 64. the second number is 3 less than the first number, the third number is 11 less than twice the first. what are the three numbers?
Assuming you mean how to solve what three consecutive numbers sum to some value: Divide the sum by three to get the middle number. The other two numbers are one less than this and one more than it. example: Which three consecutive numbers sum to 108? 108 ÷ 3 = 36 → The other two numbers are 36 - 1 = 35 and 36 + 1 = 37 → The three numbers are 35, 36, 37. 35 + 36 + 37 = 108 as required.
The numbers are 21 and 63.
Any numbers that are equivalent to 21.
No. There is only one number 700000000. Any other number is an approximation.
The two numbers that solve this problem are 5 and 15. The sum of 5 and 15 is equal to 20, and 15 is indeed 3 times 5.
-- method -- We need X numbers which are consecutive, so the middle number will be 1/ X of the total. Divide the sum of the numbers by the number of numbers ... in this case divide 186 by 3. The numbers are to be consecutive and even, so subtract 2 from the number go get one of the numbers and add 2 to the number to get the other number. You now have three numbers which are even and consecutive. Now, place a minus sign in front of them, to turn them into negative numbers For instance 12, 14 and 16 are three consecutive numbers whose sum is 42. -12, -14 and - 16 are three consecutive even integers whose sum is -42 Now you know all you need to solve the problem.
You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).
No other prime numbers are consecutive because there aren't any other even prime numbers.
11, 5, 2. two is a prime number. if you don't believe me, tell me what numbers other than itself and one go into i.
One number is 63 and the other is 21.
The number 2 is the only even prime number - all other even numbers are divisible by 2.
Two ways to solve:183/3= 61. So 61 is in the middle, and your other two numbers would be 60, and 62.The other way is algebraically. x+(x+1)+(x+2)=183 x is your starting number, and consecutive numbers would just be x+1, and x+2. Solve, to get the first number of 60, then just get 61 and 62.Final answer: 60, 61, 62.