( x2 - 121 ) = (x + 11) times (x - 11)
7x2 - 847 [First factor out a 7] 7(x2 - 121) [Now factor it totally] 7(x + 11)(x - 11) x = 11 and -11
10(11-2)
-3 minus 11=-3+-11=-14
(3)(q-11) = 3q-33
The algebraic expression for "k squared minus 11" is k ² -11. This can't be solved because it's only an expression not an equation.
No
2(2x-11)(3x+5)
11 x 11
( x2 - 121 ) = (x + 11) times (x - 11)
11x11
x2-4x-165 = (x-15)(x+11) when factored
11 x 11
Find factors of -99 which sum to -2. Solution appears to be 9 and -11 (x + 9)(x - 11)
x = -28 / -11^2
To write the expression "negative ten times the quantity two minus eleven" in numbers, you would first simplify the expression within the parentheses. Two minus eleven equals negative nine. Then, you multiply negative ten by negative nine to get positive ninety. Therefore, the expression "negative ten times the quantity two minus eleven" can be written as -10 * (2 - 11) = 90.
11 x 11 is 121.