( x2 - 121 ) = (x + 11) times (x - 11)
7x2 - 847 [First factor out a 7] 7(x2 - 121) [Now factor it totally] 7(x + 11)(x - 11) x = 11 and -11
10(11-2)
-3 minus 11=-3+-11=-14
(3)(q-11) = 3q-33
The algebraic expression for "k squared minus 11" is k ² -11. This can't be solved because it's only an expression not an equation.
No
2(2x-11)(3x+5)
11 x 11
( x2 - 121 ) = (x + 11) times (x - 11)
11x11
x2-4x-165 = (x-15)(x+11) when factored
11 x 11
Find factors of -99 which sum to -2. Solution appears to be 9 and -11 (x + 9)(x - 11)
-10 * (2-11) or -10(2-11)
x = -28 / -11^2
11 x 11 is 121.