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-4 + 10 + 6a - 2a + 3 9 + 4a
2a+2b+3a+3b+a+b= 6a+6b 2a+3a+a=6a 2b+3b+b=6b
6a2
if f(x) = 3x - 10, then whatever is put (substituted) for x in the "f(x)" bit is substituted for x in the "3x - 10" bit. Thus f(2a) = 3(2a) - 10 = 6a - 10.
6a²b - 12ab²