-4 + 10 + 6a - 2a + 3 9 + 4a
6a2
2a+2b+3a+3b+a+b= 6a+6b 2a+3a+a=6a 2b+3b+b=6b
if f(x) = 3x - 10, then whatever is put (substituted) for x in the "f(x)" bit is substituted for x in the "3x - 10" bit. Thus f(2a) = 3(2a) - 10 = 6a - 10.
6a²b - 12ab²
-4 + 10 + 6a - 2a + 3 9 + 4a
Since the question is 3(2a), then just write it out. 3(2a) is 2a+2a+2a or 6a.
= 2a - 10
10
2a-6a+9-4a+9
If you mean -2a+6a then it simplifies to 4a
6a
A=2
6a to the second power minus 8ab + 2a
5a-20+2a = 6a-11 5a+2a-6a = 20-11 1a = 9 a = 9
6a - 8 - 4a - 2 → 6a - 4a - 8 - 2 → 2a - 10
I guess you mean: 2a^2+6a Well in this case you take 2a out of the bracket and then you're left with a+3 inside. 2a(a+3a)