If 6y-8 = 28 then y = 6
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The equations are identical in value, ie the second is merely twice the first...
x=6y-4x=-2y+28Substitute (6y-4) for x in the second equation and solve for y:6y-4=-2y+288y=32y=4Then solve for x:x=6(4)-4=20(20,4)
3x + 6y = 363x - 6y = 0 add both equations6x = 36x = 63x - 6y = 03(6) - 6y = 018 - 6y = 018 = 6y3 = yThe solution point is (6, 3).
8x = 6y (8/6)x = y (4/3)x = y Let x = 3, 6, and 9, then y = 4, 8, and 12. So that for any value of x, you will find a correspoinding value for y.
4(3x+6y = 42) 3(-7x+8y = -109) Multiply all terms in the top equation by 4 and in the bottom by 3: 12x+24y = 168 -21x+24y = -327 Subtract the bottom equation from the top remembering that a minus from a minus is equal to a plus: 33x = 495 Divide both sides by 33: x = 15 Substitute the value of x into the original equations to find the value of y: Therefore: x = 15 and y = -1/2