It would be 15inches
The length would be 39 feet and the width 36 feet for a perimeter of 150 feet
12 feet
30
3 feet
80 = 2x + 2(x+6)80 = 4x + 1268 = 4xx = 17Dimensions are x by (x+6), so:17x23Check:Permimeter = 2x + 2y (17*2)+(23*2) = 80, therefore correct
Let the length be 2x and the width be x: length*width = area 2x*x = 50 2x2 = 50 x2 = 25 x = 5 feet
The length would be 39 feet and the width 36 feet for a perimeter of 150 feet
A = area, L = length, W = width A = LW L = 2W A = (2W)W = 2W2 2W2 = 50 W = 5 ft
12 feet
4Improved Answer:-30 feet of fencing will be needed
If the perimeter is 84 feet and the length is twice the width, then the length will be 28 feet and the width will be 14 feet.
Width = 16 feet Length = 38 feet
Let W = width of garden. Therefore 4W = length of garden. Area is length x width, ie W x 4W = 256 sq ft. Rewrite as: 4W2 = 256 W2 = 256/4 = 64, therefore W = 8ft, and length = 32ft. So total length of fence required is (2x8) + (2x32) = 80 ft. Happy building!
Let the length be 4x and the width be x: 2(length)+width = 45 feet of fence used 2(4x)+x = 45 feet 8x+x = 45 9x = 45 x = 5 length = 20 ft and the width = 5 ft Check: 2(20)+5 = 45 ft
the length of a rectangular garden is 2 feet longer than 3 times it's width .if the perimeter of the garden is 100 feet find the width and length of the garden
Perimeter maximum 150 so Length + Width = 75; Best fit is 39 ft long and 36 ft wide
The garden has to be 36-ft by 39-ft. 150-ft of fence will just enclose it, and the area is 1,404 square feet. If the length didn't have to be 3-ft more than the width, then he could make it 37.5-ft square. The same 150-ft of fence would enclose it, but the area would be 1,406.5 square feet ... a full 0.16%, or 2.5 square feet, more.