Sue is 8 years old.
Sue (8) + Leah (14) + John (19) = 41
Solve algebraically by stating all ages in terms of Leah's (L)
Sue S = L - 6 (Leah = Sue + 6)
John J = L + 5 (Leah = John + 8)
S + J + L = 41
(L-6) + (L+5) + L = 41
3L -1 = 41
3L = 42
L = 14
S = 8
J = 19
No. Albert was about 3 years older than his sister.
Sister = 5 David = 13
8
use an equation x=sue x+x+6+x+11=41 -17 -17 3x= 24 /3 /3 x= 8 sue is 8
Thomas is 30 years and Huilan is 41 years
No. Albert was about 3 years older than his sister.
30 duhh!your a idiot...... its 8
Mozart's sister was five years older than he was.
100 years
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He has a half-sister about ten years older than he.
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His sister is 13 years old
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Older sister 6 years older emmalee Browne
Forty years (Numbers ch.14).
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