Expand z plus 11 times z plus 11 = (z+11)(z+11) = z2 + 22z + 121.
L = S + 11; 2S + 3(S + 11) = 123, ie 2S + 3S + 33 = 123ie 5S = 90 ie S = 18 and L = 29
(x + 3)2 = 11 + (x + 2)2x2 + 6x + 9 = 11 + x2 + 4x + 46x - 4x = 11 + 4 - 92x = 6x = 3Check: (3 + 3)2 = 11 + (3 + 2)2 ? ie 36 = 11 + 25 ? Yes. There you have it.
For example, -1 times 11.
Let the unknown number be called x: 3x-11 = x+33 3x-x = 33+11 2x = 44 x = 22 So the number is 22
Let the number be x4x-3(x+2)=54x-3x-6=5x=11
4/5 times x = 11
One possible answer is 1 times 99.
7 (Seven) is the next number in your sequence ! Plus four minus two plus four minus two plus four minus two and so on and so on !
Expand z plus 11 times z plus 11 = (z+11)(z+11) = z2 + 22z + 121.
11
4/.4 + 4/4 = 10 + 1 = 11.
'Some number' is referred to as 'x' , the unknown , but fixed value. Hence 3x + 11
4/7 plus 8/15 = 116/105 or 1 and 11/105 as a mixed number
Two times the square root of three plus five times the square root of three plus four times the square root of three equals eleven times the square root of three.
Probably 11!11! which is between 10303,413,813 and 10 times that.
Suppose the number is x. Then 4x + 7x = 44 ie 11 x = 44 Divide both sides by 11 to give x = 4.