What_is_the_area_bounded_by_the_graphs_of_fx_and_gx_where_fx_equals_xcubed_and_gx_equals_2x-xsquared
Since g(x) is known, it helps a lot to find f(x). f(g(x)) is a new function composed by substituting x in f with g(x). For example, if g(x) = 2x + 1 and f(g(x)) = 4x2+ 4x + 1 then you you recognize that this is the square of the binomial 2x + 1, so that f(g(x)) = (f o g)(x) = h(x) = (2x + 1)2, meaning that f(x) = x2. if you have a specific example, it will be nice, because there are different ways (based on observation and intuition) to decompose a function and write it as a composite of two other functions.
graph gx is the reflection of graph fx and then transformed 1 unit down
at first draw the graph of fx, then shift the graph along -ve x-axis 21 unit
The values of x such as fgx= gfx is math. It comes down to finding the value of the letter X.
What_is_the_area_bounded_by_the_graphs_of_fx_and_gx_where_fx_equals_xcubed_and_gx_equals_2x-xsquared
4
Since g(x) is known, it helps a lot to find f(x). f(g(x)) is a new function composed by substituting x in f with g(x). For example, if g(x) = 2x + 1 and f(g(x)) = 4x2+ 4x + 1 then you you recognize that this is the square of the binomial 2x + 1, so that f(g(x)) = (f o g)(x) = h(x) = (2x + 1)2, meaning that f(x) = x2. if you have a specific example, it will be nice, because there are different ways (based on observation and intuition) to decompose a function and write it as a composite of two other functions.
graph gx is the reflection of graph fx and then transformed 1 unit down
Yes, the integral of gx dx is g integral x dx. In this case, g is unrelated to x, so it can be treated as constant and pulled outside of the integration.
at first draw the graph of fx, then shift the graph along -ve x-axis 21 unit
graph G(x)=[x]-1
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
f(t) = t^2 + t F(t) = (1/3)t^3 + (1/2)t^2 ---- g(x) = 2sin(2x) G(x) = -cos(2x) ---- h(x) = 5x H(x) = (5/2)x^2 ---- p(x) = cos(x) + cos(2x) P(x) = sin(x) + (1/2)sin(2x) ---- q(x) = e^x Q(x) = e^x
In A-sharp minor, every single note has a sharp. For the harmonic minor, the G♯ is raised to Gx (both ways) and for the melodic minor Fx and Gx is used on the way up but is reverted back to the key signature (normal F♯ and G♯ on the way down).
The values of x such as fgx= gfx is math. It comes down to finding the value of the letter X.
If you want to ask questions about the "following", then I suggest that you make sure that there is something that is following.