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The first angle A is twice as large as the second, angle B. The third angle C is 20 degrees larger than B (as B must be the smallest angle). The internal angle sof a triangle add to 180 degrees.

A + B + C = 180

A = 2B

C = B + 20

(2B) + B + (B + 20) = 180
4B + 20 = 180
4B = 160
B = 40o.

A = 2B
A = 2 X 40
A = 80o.

C = B + 20
C = 40 + 20
C = 60o.

Alternate Method

The internal angles of all triangles always add up to 180 degrees. Call our triangle angles A,B and C respectively

A+B+C = 180°

All the dimensions of the triangle are described in terms of angle A; the smallest angle.

A= A, B = 2A, C = A + 20o

So in terms of A:

A +2A + A+20o 180o

4A +20o = 180o therefore 4A = 180o - 20o = 160o and therefore A = 160/4 = 40o


If A= 40o and B = 2A and C = A + 20o

Then

A = 40o, B = 80o, C = 60o

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Q: If one angle of a triangle is twice as large as another The measure of the third angle is 20 degrees greater than that of the smallest angle How large are the angles?
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