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If the area of triangle ABC is 27cm2 BC is 12cm and angle BCA is 98 degrees what is length AC?
Gsprules
Area = 1/2*a*b*sin(C)
where a = BC, b = AC and angle C = angle BCA
27 = 0.5*12*AC*sin(98)
So AC = 27/[0.5*12*sin(98)] = 4.54 approx.
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∙ 11y ago
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