Let x = width of the box. We know that the length = 3x, and that the perimeter is 2*length + 2*width, thus we have the equation
2*(3x) + 2*x = 64
=> 6x+2x = 64
Combining like terms:
=> 8x = 64
Solving for x by dividing both sides by 8:
x=8
Thus we know that the width is 8, and length = 3*x =3*8 = 24
Area = width*length = 8*24 = 192
15 feet.
64 meters
The area is the length times the width. The perimeter is two times the length plus two times the width.
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
2 times length plus 2 times width = perimeterhalf the perimeter of a rectangle
the length is equal to 160,083
Tripling the side lengths of a rectangle will triple its perimeter. The perimeter of a rectangle is calculated as ( P = 2(length + width) ). If both the length and width are multiplied by three, the new perimeter becomes ( P' = 2(3 \times length + 3 \times width) = 3 \times P ). Therefore, the perimeter increases by a factor of three.
15 feet.
63 feet
Width: 8.5 Length: 25.5
dont is answer
64 meters
call width x so length is 3x perimeter is (2*length)+(2*width) so perimeter is 8x
2 times (length + width)
The perimeter of a rectangle is calculated using the formula ( P = 2 \times (length + width) ). For a rectangle with a length of 30 meters and a width of 20 meters, the perimeter would be ( P = 2 \times (30 + 20) = 2 \times 50 = 100 ) meters. Thus, the perimeter of the rectangle is 100 meters.
The perimeter of a rectangle is calculated using the formula ( P = 2 \times (length + width) ). For a rectangle with a length of 16.8 units and a width of 9.6 units, the perimeter is ( P = 2 \times (16.8 + 9.6) = 2 \times 26.4 = 52.8 ) units. Therefore, the perimeter of the rectangle is 52.8 units.
Area is length times width, perimeter is twice the sum of length and breadth.