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Earn +20 ptsQ: If x equals 3 and y equals 9 then 7x add 4y equals?
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What are the solutions to the equations 7x-4y equals 13 and 2x-5y equals -4?
It works out that the solutions are: x = 3 and y = 2
Simplify the algebraic expression 7x squared minus 4y plus 3x squared plus 5y plus 2 and evaluate it for x equals 3 and y equals 9?
7(3y-2)-(-4y+9)
5x-3y equals 23 7x-4y equals 33?
5x -3y = 23 7x - 4y = 33 This is simultanreous equations. Arbitrarily decide which letter to eliminate. In this case 'y' To do this multiply the top eq'n by '-4' and the bottom by '3' Hence -20x + 12y = -92 21x - 12y = 99 Add the two eq'ns. This will eliminate 'y' x = 7 Substitute into either eq'n for 'y' 49 - 4y = 33 -4y = - 16 y = 4 Hence (x,y) = ( 7,4)
8 x-1 equals 7x plus 2 Answer?
8x-1 = 7x+2 Add 1 to both sides: 8x = 7x+3 Subtract 7x from both sides: 1x = 3 ie x = 3
What is the solution of 4y - 3 greater than 9?
y > 3 Treat the greater than sign [a bit] like an equals sign to solve: 4y - 3 > 9 ⇒ 4y > 12 [add 3 to each side] ⇒ y > 3 [divide each side by 4]
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