It works out that the solutions are: x = 3 and y = 2
7(3y-2)-(-4y+9)
5x -3y = 23 7x - 4y = 33 This is simultanreous equations. Arbitrarily decide which letter to eliminate. In this case 'y' To do this multiply the top eq'n by '-4' and the bottom by '3' Hence -20x + 12y = -92 21x - 12y = 99 Add the two eq'ns. This will eliminate 'y' x = 7 Substitute into either eq'n for 'y' 49 - 4y = 33 -4y = - 16 y = 4 Hence (x,y) = ( 7,4)
8x-1 = 7x+2 Add 1 to both sides: 8x = 7x+3 Subtract 7x from both sides: 1x = 3 ie x = 3
y > 3 Treat the greater than sign [a bit] like an equals sign to solve: 4y - 3 > 9 ⇒ 4y > 12 [add 3 to each side] ⇒ y > 3 [divide each side by 4]
It works out that the solutions are: x = 3 and y = 2
3x - 2y + 7x + 4y = 3x + 7x - 2y +4y = (3+7)x + (-2+4)y = 10x + 2y
It works out that: x = 3 and y = 2
7(3y-2)-(-4y+9)
Add 3 to 46 then divide by 7.
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5x -3y = 23 7x - 4y = 33 This is simultanreous equations. Arbitrarily decide which letter to eliminate. In this case 'y' To do this multiply the top eq'n by '-4' and the bottom by '3' Hence -20x + 12y = -92 21x - 12y = 99 Add the two eq'ns. This will eliminate 'y' x = 7 Substitute into either eq'n for 'y' 49 - 4y = 33 -4y = - 16 y = 4 Hence (x,y) = ( 7,4)
Add the two equations and get 4x = 12 so x = 3 and y = -1
8x-1 = 7x+2 Add 1 to both sides: 8x = 7x+3 Subtract 7x from both sides: 1x = 3 ie x = 3
7Y = 33-4Y ( add 4Y to both sides of equation ) 11Y = 33 ( divide both sides of equation by 11 ) Y = 3
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A1: 7x-4y=9 , 3x+2y=15 and 7x-4y=9, 6x+4y=30 so 13x=39 x=3 now plug it in for y 9+2y=15 so y=3 A2: The right expression is missing a + or - between the 3x and 2y. For the purpose of this demo, let's assume it is 3x+2y-15. It can be solved by multiplying the right expression by 2, then add the expressions. That will eliminate y. Then solve for x. When x is known, plug its value into either of the expressions and solve for y. To start: 2(3x+2y-15)=6x+4y-30 adding the two (7x-4y-9)+(6x+4y-30)=13x+0y-39=13x-39 solve for x