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So, assuming y = (x + 3)^2, then if x = 5, y = 64.
x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
x2 + 12x + 32 = (x + 8)(x + 4)
what is
66
The value of X in the equation 2.9 plus x plus 7.5 = 6 is -4.4.
If you mean: 7+x = 32 then the value of x is 25
x < -26.
x5+4x4-6x2+nx+2 when divided by x+2 has a remainder of 6 Using the remainder theorem: n = 2
5x + 5y = 5(x+y)
8x+32 is an expession and can't be solved unless a value for x is given.
3xy = 3 times 5 x 2 = 30 4y cubed = 4 times 2 x 2 x 2 =32 Total value 62
is a quintic expression in x (NOT an equation).
It is an equation and the value of x is 32/3
7
Applying BODMAS, 32 - (15 x 2) + 3 = 5
32 + x = 71 32 - 32 + x = 71 - 32 x = 39
x + 32 = 55 x = 55 - 32 x = 23