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So, assuming y = (x + 3)^2, then if x = 5, y = 64.
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How do you solve x - x x?
x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
Factor the following polynomial x2 plus 12x plus 32?
x2 + 12x + 32 = (x + 8)(x + 4)
2x -64 what is the value of x?
66
What is the value of x in the equation 7x - 3 32?
X = 5 7x5 = 35 - 3 = 32
2.9 plus x plus 7.5 6?
The value of X in the equation 2.9 plus x plus 7.5 = 6 is -4.4.
7 plus blank 32?
If you mean: 7+x = 32 then the value of x is 25
What is the value of n in the expression x5 plus 4x4 minus 6x2 plus nx plus 2 that has a remaider of 6 when divided by x plus 2?
x5+4x4-6x2+nx+2 when divided by x+2 has a remainder of 6 Using the remainder theorem: n = 2
What is the value of x in 2x PLUS 6 IS GREATER THAN 3x PLUS 32?
x < -26.
How do you factorize x5 plus y5?
5x + 5y = 5(x+y)
How do you solve 8x plus 32?
8x+32 is an expession and can't be solved unless a value for x is given.
What is the value of the expresion 3 xyplus 4 ycubed when x5 and y2?
3xy = 3 times 5 x 2 = 30 4y cubed = 4 times 2 x 2 x 2 =32 Total value 62
What is x5 plus 10x4 plus 8x3 plus 4x plus 2?
is a quintic expression in x (NOT an equation).
What is x to the fifth power plus x to the second power minus 4 divided by x plus 3?
7
What is 5 plus 3x-2 equals 35?
It is an equation and the value of x is 32/3
What is value of 32-15 times 2 plus 3 is?
Applying BODMAS, 32 - (15 x 2) + 3 = 5
32 plus x equals 71?
32 + x = 71 32 - 32 + x = 71 - 32 x = 39
How do you solve x - x x?
x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
