If you have 2.35 in dimes and nickels and you have one more dime than nickels how many of each do you have?

Answer 1

10.9

Answer 2

Let's represent the number of nickels as "N" and the number of dimes as "D." Since you have $2.35 in total, we can set up the equation 0.05N + 0.10D = 2.35. Additionally, we know that there is one more dime than nickels, so we have the equation D = N + 1. By substituting the second equation into the first and solving simultaneously, we find that N = 9 and D = 10. Therefore, you have 9 nickels and 10 dimes.

Answer 3

Set up your equations based upon the following: Let N = number of nickles. Let N + 1 = number of dimes. Let 5N = the value (in cents) of all the nickles. Let 10(N + 1) = the value (in cents) of all the dimes. Let 235 = the total value (in cents) of all the coins (nickles and dimes). In English, the value of the dimes plus the value of the nickles equals the total value of the coins. Algebraically, we write: 5N + 10(N + 1) = 235 The distributive law of multiplication lets us rewrite that this way: 5N + 10N + 10 = 235 Grouping lets us write that this way: 15N + 10 = 235 Subtracting 10 from both sides of the equation yields: 15N = 225 Dividing both sides by 15 yields: N = 15 So, we have 15 nickles and 15 + 1, or 16, dimes.