what is the solution of x-5y=10 and 2x-10y=20
(10, 2)
x = 3, y = 3
2x-5y+15=0 -5y=-2x-15 y=(2/5)x+3
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
what is the solution of x-5y=10 and 2x-10y=20
(10, 2)
It is.
3x + 5y = -1 2x - 5y = 16 Add the two equations: 5x = 15 or x = 3 Substitute for x in the first equation: 3*3 + 5y = -1 15 + 5y = -1 5y = -10 so y = -10/5 = -2 The solution is (x, y) = (3, -2)
2x-5y = -10 -5y = -2x-10 y = 2/5x+2 which is in slope intercept form
-5y +2x = -10 -5y = -2x -10 y = 2/5x +2 So the slope = 2/5 and the y intercept = 2
Put in this form. Y = mX + c 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
2X - 5Y = 10 subtract 2X from each side - 5Y = - 2X + 10 divide each side by - 5 Y = 2/5X - 2 slope(m) = 2/5
If: 2x+5y = -10 Then by subtracting 2x from both sides: 5y = -2x-10 And dividing all terms by 5: y = -2/5x-2 which is now in slope intercept form
2x - 5y = -10 So 5y = 2x + 10 and therefore y = (2/5)*x plus something So the slope is 2/5 or 0.4
2x + 5y = 16 -2x - 3y = -14 2y = 2 y = 1 / x = 5.5 (5.5,1) or (5 1/2,1)
2X - 5Y = 10 ???? If so. 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================