No, 3.6 is not a perfect square. A perfect square is defined as a number that has a whole number for a square root. In other words, there's no whole number that, when multiplied by itself, equals 3.6.
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it is not a perfect square since there is no integer, say x, where x^2=6. however, 6 is a perfect number. this is because its factors(aside from itself), add up to the number 6 itself-- 1+2+3=6.
It is: 36 because 6*6 = 36
6.
The square root simplifies to six times the square root of five. The decimal form of that is approximately 13.41640786
No; you can prove the square root of any positive number that's not a perfect square is irrational, using a similar method to showing the square root of 2 is irrational.