Best Answer

I guess your two equations are:

- 4x - 6y = 2
- 2x + 3y = 12

Since the plus (+) and equals (=) signs have been stripped from your question.

If this is the case, then they are not parallel since their gradients are not the same.

Without working them out exactly, it can be seen that one is positive (equation 1.) and the other is negative (equation 2.):

- 4x - 6y = 2 ⇒ 6y = 4x - 2 ⇒ +ve gradient
- 2x + 3y = 12 ⇒ 3y = -2x + 12 ⇒ -ve gradient

Q: Is 4x-6y2 parallel to 2x 3y12?

Write your answer...

Submit

Still have questions?

Continue Learning about Algebra

y = 2x

If you mean: y = 2x-4 and (1, 5) then the parallel equation is y = 2x+3

[ y = 2x plus or minus any number ] is parallel to it. [ y = -0.5x plus or minus any number ] is perpendicular to it.

anything with the same slope as that line which I'm guessing is 2Answer:You mean y=2x-11 ? If so, then a parallel line would be:y= 2x + (any number)

I assume the question should be y = -2x + 5? The equation of a line that is parallel to that line is any line that begins 7 = -2x ... after the -2x any number may be added or subtracted. Parallel lines have the same slope. In the original equation, the slope is -2.

Related questions

2y= 3x+6

y=2/3x+4

If you mean: 2x+3y = 12 then y = -2/3x+4 whereas -2/3 is the slope and 4 is the y intercept

If you mean: 6x+3y = 12 then it is y = -2x+4 in slope-intercept form

If you mean: 6x+3y = 12 then it is y = -2x+4 in slope-intercept form

If you mean: 2x+4y = 6 then 2x+4y = 12 is parallel to it because parallel lines retain the same slope but have different y intercepts

[ y = -2x + any other number ] is parallel to [ y = -2x + 6 ].

If you mean: 6x-3y = 12 Then: -3y = -6x+12 And: y = 2x-4 So: the slope is 2 and the y intercept is -4

y = 2x

Any line which has a gradient which is not 2 will not be parallel to the line y = 2x + 1.

If the second equation is: y minus 2x equals 3, then:y - 2x = 3 ⇒ y = 2x + 3 and it is parallel to y = 2x.Otherwise (with with missing operator as "plus", "multiply" or "divide"), the lines are neither parallel nor perpendicular.

5