If you mean: 2y = -4x-12 then y = -2x-6 and -6 is the y intercept
2y - 4x = -12 Algebraically rearrange to 2y = 4x - 12 Divide both sides by '2' y = 2x - 6 So at the 'y' intercept, x = 0 Substituting x = 0 We have y = 2(0) - 6 Anything multiplied '0' is equal; to '0' Hence y = 0 - 6 y = -6 is the value of the y-intercept.
4x+2y = 6 2y = -4x+6 y = -2x+3 Perpendicular slope is 1/2
It simplifies to: -4x-12
4x + 2y = 6
4x-2y = 12 -2y = -4x+12 y = 2x-6 Therefore the y intercept is -6 and the slope is 2
4x+2y = 12 2y = -4x+12 y = -2x+6 So the y intercept is 6 and the slope is -2
The y-intercept of the graph of 4x + 2y =12 is probably 6
2y-4x=-12 Add 4x to each side 2y=4x-12 Divide each side by 2 y=2x-6 The y-intercept is (0,-6)
If you mean: 2y = -4x-12 then y = -2x-6 and -6 is the y intercept
No because without an equality sign the given expression can't be considered to be an equation.
No because without an equality sign the given expression can't be considered to be an equation.
2y - 4x = -12 Algebraically rearrange to 2y = 4x - 12 Divide both sides by '2' y = 2x - 6 So at the 'y' intercept, x = 0 Substituting x = 0 We have y = 2(0) - 6 Anything multiplied '0' is equal; to '0' Hence y = 0 - 6 y = -6 is the value of the y-intercept.
If: 2y-4x = -12 Then: y = 2x-6 So the y intercept is -6 and the slope is 2
-6
If the two equations are (i) 4x + 2y = 12 and (ii) x + 2y = 6, proceed as follows: Rewrite (ii) as x = 6 - 2y; substitute this expression for x into (i) to result in 4(6 - 2y) + 2y = 12, or 24 - 8 y + 2y = 12, or - 6 y = 12 -24 = -12, or y = -12/-6 = 2. Then, back to (ii) again, x = 6 - 2(2) = 2.
The easiest way to solve this will be to put the question in the slope-intercept form, y=mx+b. Then the y-intercept will be b. 2y-4x=-12 2y=4x-12 y=2x-6 So the y-intercept is -6.