that depends on the number. sqrt(2) is irrational, sqrt(4)=2 is rational
It is equal to 21/2 which is a rational number
Sometimes it is and sometimes it isn't. The square root of 2 and the square root of 3 are both irrational, as is their product, the square root of 6. The square root of 2 and the square root of 8 are both irrational, but their product, the square root of 16, is rational (in fact, it equals 4).
No; you can prove the square root of any positive number that's not a perfect square is irrational, using a similar method to showing the square root of 2 is irrational.
The square root of a positive integer can ONLY be:* Either an integer, * Or an irrational number. (The proof of this is basically the same as the proof, in high school algebra books, that the square root of 2 is irrational.) Since in this case 32 is not the square of an integer, it therefore follows that its square root is an irrational number.
It is rational. The root of a perfect square, such as 4, is rational; the root of any positive integer that is not a perfect square is an irrational number.
irrational
The square root of (any number that isn't a perfect square) is irrational.
the square root of 2 fifths of irrational is 0.565685425
The square root of 4 is 2 which is a rational number
sqrt(32) = 4sqrt(2) The square root of '2' is irrational, so the square root of '32' is irrational.
irrational
The square roots of 2 and 3 are irrational but not transcendent.
No; √2 is irrational.
1, 2 are rational and square root of 2 and pi are irrational.
The square root of 2 is irrational. In general, the square root of a positive integer is either an integer (if you take the square root of a perfect square), or it is irrational.
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