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yes , u can :

check this : http://mathforum.org/library/drmath/view/57803.html

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Q: Is it possible to divide a hexagon into eight equal parts?
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Related questions

How can you divide a hexagon into 6 equal parts?

Partitioning a general hexagon into 6 equal parts is normally extremely difficult..


Is it possible for a hexagon to have all 6 angles equal and not be a regular hexagon?

yes because all of the sides are equal


How can you divide a hexagon into 8?

Select any point inside the hexagon and draw a line segment to any point on the boundary of the hexagon. Draw 7 more such segments. These will divide the hexagon into 8 parts. The parts will not be equal but that was not a requirement of the question.


How do you divide a hexagon into equal halves?

In general, there is no simple way of doing so.


How do divide a hexagon into 3 equal parts?

dont ask me, ask mathematicions


How do you divide a hexagon into nine equal parts?

Divide it into 72 pieces, group them into groups of 8. DoNe


Is drawing a regular hexagon possible?

Yes and it will have 6 equal sides


What has equal sides and eight faces?

A hexagon. (A six-sided shape) * * * * * A regular octahedron.


If a shape is a regular hexagon with eight sides what must be true?

False because a regular hexagon has 6 equal sides and not 8 sides


How do you divide hexagon into 3 equal parts?

Draw a line from midpoint of every other side to the center.


How do you divide a hexagon into three equal parts?

This provided illustration (below) might not be terribly accurate but the three equal parts are meant to be the shapes of three rhombus'. All three lines join up in the center of the hexagon.______/ \ \/ \ \/ \____\ Hexagon divided into 3 equal rhombuses.\ / /\ / /\ /____/


What is the exterior angle of a hexagon?

what are the exterior Angles of a hexagon, heptagon, octagon, decagon and an icosagon ?If all the exterior angles of a hexagon or any polygon equal 360, then just divide by the number of vertices and there's one exterior angle of the polygon.