Sometimes the square root of a positive number can be irrational, as in the square root of 2 (which is a non-perfect square number), but sometimes it is a rational number, as in the square root of 25 (which is a perfect square number).
No, 25 is a rational number; it is an integer, and all integers are rational.
If the value applied in the radical is not a perfect square, it is irrational. 25; 400; and 625 are perfect squares and are rational when applied in a radical.
Rational. It's the ratio of 14 to 25 .
An example is the square root of a number. Ex: square root of 2. This is 1 example, not the main one. Any cube root or square root which doesn't give a perfect number is an irrational number. Ex; square root and cube root of 5, since their answer will be 2.24 and 1.70 which are not perfect numbers like square roots of 25 and 64 or cube roots of 27 and 216.
The square root of 25 is 5, which is a rational number.
The square root of 25 is 5 which is a rational number
The square root of 25 is 5 which is a rational number * * * * * Or -5, which is also rational.
No, they are both rational.
They are +5 and -5, which are both rational.
The square root of 8 over 25 is irrational, and real.
No because as for example the square root of 25 is 5 which is a rational number
The sqrt of 25 = 5 which can be written as a recurring decimal. Therefore no, it is not irrational, it is rational.
The square root of 25 is 5, which is a whole number, an integer, a natural number and a rational number.
The square root of 25 is 5 ... rational.