The square root of 49 is 7 and it is a natural number because natural numbers are from 0-infinity
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The square root of 49 is 7, so it is rational.
the 4th root of 49 is the square root of the square root of 49 since square root 49 =7 then simplify is square root of 7
The square root of 49 is 7. The square root of 64 is 8. The square root of any number between 49 and 64 is between 7 and 8.
No because 7 is a rational number
Lots of them. 6² = 36 and 7² = 49, so any number between 36 and 49 will have a square root between 6 and 7. So 37, for example, has a square root of approx 6.32 and 48 has square root of approx 6.93
No - a natural number is a whole number. Therefore, the square root of 49 is a natural number, but the square root of 50 is not.
The negative square root of 49 is -7. -7 is whole, integer, and rational number. It's not a natural or irrational number.
The square root of 49 is 7 or -7.
Yes. The square root of 49 is 7.
The square root of 49 is 7, so it is rational.
squaring a number is when you times it by itself the square root of a number is the actual base number e.g the square root of 49 is 7 and 7x7=49
A square root is a number that is multiplied by itself to get the number here's an example. 7 is the square root of 49 (7*7=49)
7 7 x 7 = 49 so sqrt(49) = 7
As an example, the square root of 49 is 7. It's this because the square root of a number is another number multiplied by itself(7X7=49).
The square root of a negative number is considered an imaginary number. In this case, the square root of -49 is 7i, where i represents the imaginary unit (√-1). This is because when you square 7i, you get -49.
Yes, a square number means that it is the product of a number times the same number, so if you can divide a number buy the same number you get the square root. 6x6=36 and the square root of 36 is 6. 7x7 is 49 and the square root of 49 is 7. Make sense?
no, 28 has no whole square root; the square root of 49 is 7