sqrt(6) = sqrt(2 x 3) = sqrt(2) X sqrt(3)
Since '2' & '3' are prime numbers, their square roots are Irrational.
Hence
sqrt(2) X sqrt(3) = 1.4142... X 1.73205.... = 2.449489743... Is also irrational.
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It is irrational. * The square root of any positive integer, except of a perfect square, is irrational. * The product of an irrational number and a rational number (except zero) is irrational.
No because the square root of 36 is 6 which is a rational number
The square root of 36 is 6 which is a rational number because it can be expressed as an improper fraction in the form of 6/1
No; you can prove the square root of any positive number that's not a perfect square is irrational, using a similar method to showing the square root of 2 is irrational.
Sometimes it is and sometimes it isn't. The square root of 2 and the square root of 3 are both irrational, as is their product, the square root of 6. The square root of 2 and the square root of 8 are both irrational, but their product, the square root of 16, is rational (in fact, it equals 4).