In short, yes.
On the left side there is 1 Carbon, 4 Hydrogen and 4 Oxygen.
There is the same amount on these on the right.
Remember 2H20 is the same as H402. The 2 in front of the water acts upon everything in the molecule.
The coefficients are the numbers written in front of the chemical formulas in a chemical equation, and tells how much of a certain substance is involved in the reaction. When there is no number, it is understood to be one. For example, the following equation, which represents the combustion of methane (CH4), could be read in a couple of different ways. CH4 + 2O2 --> CO2 + 2H2O One molecule of methane plus two molecules of oxygen produces one molecule of carbon dioxide plus two molecules of water. or One mole of methane plus two moles of oxygen produce one mole of methane plus two moles of water.
i have NO idea which math book ur talking about, so i dont know the answer, sorry!
Make sure atoms on both sides are equal.Balanced equation as follows. CH4+2O2---->CO2+2H2O
Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
Unbalanced CH4 + O2 = H2O + CO2 Balanced CH4 + 2O2 = 2H20 + CO2
Ch4 + 2o2 à co2 + 2h2o
CH4 + 2O2 --> CO2 + 2H2O
Ch4+2o2--->co2+2h2o+heat
Ch4+ 2o2 ---> 2h2o + co2
If you're talking about a chemical equation for a situation where you have an environment containing only methane and propane, there can be no balanced equation because with no oxygen, neither gas will burn.
I assume you were looking to balance the reaction: CH4 + 2O2 --> CO2 +2H2O
CH4 + 2O2 → CO2 + 2H2O.
Hydrogen combines with oxygen at the completion of a combustion reaction to form water. The following is the balanced equation for the combustion of methane (CH4). CH4 + 2O2 ---> CO2 + 2H2O
The product in the reaction of CH4 + 2O2 => CO2 + 2H2O is carbon dioxide (CO2) and water (H2O).