It is: (x+1)(x+4) none of which are prime numbers
x2 + 6x + 8 =(x + 2)(x +4)
That factors to (x - 2)(x + 4) x = 2, -4
-3.
X = √63
No. it's not a prime number when x = 40, 41, 81,82 ...
(x+4)(x+4), or (x+4)^2.
Oh, dude, you're hitting me with some math now? Alright, so you're looking at the quadratic expression x^2 + 5x + 4. To factor this, you want to find two numbers that multiply to 4 (the constant term) and add up to 5 (the coefficient of the x term). Those numbers are 1 and 4, so the factored form is (x + 1)(x + 4). That's it, easy peasy lemon squeezy!
(x + 4)(x +4) or (x + 4)squared
Let square = [x] -4+3*(-2)*[-4]+[3x-2x]=-4-6-2+[x]=-12+[x]The answer is negative 12 plus squared x.
-2
It is (x+3)(x+4) when factored
4(x+y)^2
(-4,-6)
(x-1)(x-4)
4
It is: (x+1)(x+4) none of which are prime numbers