Yes, y=x^2 is a non-linear function. In fact it is a parabola. Graphing one is quite easy using a table of values or other methods.
X = √63
2 x cosine squared x -1 which also equals cos (2x)
So u have the function x2-4=0 Now because 4 is a squared number, its square root is 2 (x+2)(x-2)=0
(2, -2)
If x squared = 40 then x = square root of 40 = +/- 6.3255555
No, it is not an example of a nonlinear relationship because there is a steady rate of change.
X squared is not an inverse function; it is a quadratic function.
No it is not.
No.
The vertex is at the point (0, 4).
X = √63
8
no, because xx=x squared, and x squared is not linear
22
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
Yes
X squared = x+6 6+x=x squared X=6