Let x be the number of nickles. So, the number of dimes is 40 - x. So,
0.05x + 0.10(40 - x) = 3.50
0.05x + 4 - 0.10x = 3.50
- 0.05x + 4 = 3.50 subtract 4 to both sides;
-0.05x = - 0.50 divide by - 0.05 to both sides;
x = 10
Thus, Jack has 10 nickles and 30 dimes.
She has 11 nickels.
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This problem can be solved by solving the system of equation. Total worth of coins: $2.65 Total number of coins: 33 n= number of nickels q= number of quarters since we know that there are 33 coins total, we can set the equation like this: number of nickels + number of quarters = total number of coins => n+q=33 We also know that the worth of these coins is $2.65. each nickel is worth of $0.05 each quarter is worth of $0.25 therefore we can set the equation: 0.05 x number of nickels + 0.25 x number of quarters = total worth of coins. 0.05n+0.25q=2.65 However, for convienience, we should multiply the equation above by 100 to get rid of decimals. Thus it is 5n+25q=265 you will now have a following set of 2 equations: n+q=33 5n+25q=265 Use the SUBSTITUTION METHOD to solve either n or q for solving n: (replace q with n if you're willing to solve q instead) n+q=33 => n=33-q (since n is equal to 33-q, we can -q -q substitue n in the other equation.) 5(33-q)+25q=265 => 165-5q+25q=265 => 20q=100 => q=5 -165 -165 /20 /20 There are 5 quareters as a result.(or 28 nickels) since you know that q=5 you can substitute q in the first equation. n+(5)=33 => n=28 - 5 -5 therefore, there are 5 quarters and 28 nickels. ELIMINATION METHOD: n x -5 + q x -5 = 33 x -5 => -5n-5q=-165 5n+25q=265 + 5n+25q=265 ------------- 20q=100 => q=5 /20 /20 Or simply we can say: if we have x quarters, we have .25x value of them. So the value of nickels will be 2.65 - .25x. Since we have 33 coins, and x quarters, then the number of nickels will be 33 - x. So the value of all nickels would be also .05(33 - x). Thus, we have:2.65 - .25x = .05(33 - x)2.65 - .25x = 1.65 - .05x2.65 - 1.65 - .25x + .25x = 1.65 - 1.65 - .05x + .25x1 = .20x1/.20 = .20x/.20x = 5 the number of quarters 33 - x= 33 - 5= 28 the number of nickels. Thus, we have 5 quarters and 28 nickels.
The 8 coins are: 3 quarters, 2 dimes, 1 nickel and 2 pennies.
32
4 nickels and 5 quarters
m>$2.00
She has 11 nickels.
4
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Pocket Full of Nickels-Te Adoro - 2013 was released on: USA: 13 November 2013 (International Puerto Rican Heritage Film Festival)
11 dimes.
One quarter,or 25 pennies, or 20 pennies and 1 nickel, or 15 pennies and 2 nickels, or 10 pennies and 3 nickels or 5 pennies and 4 nickels, or 2 dimes and 1 nickel, or 1 dime and 3 nickels, or 15 nickels and 1 dime.
7 nickels, 4 dimes, and 3 quarters.
5 cents. The only nickels to contain silver are the "war nickels" produced from 1943-1945 with a large mintmark over the Monticello. 1964 nickels use the same composition as today, have a high mintage and are easily found in pocket change. They are worth no more than 5 cents. There were over 2 billion nickels minted that year.
Look at your pocket change, likely you will find more 1999 nickels so just spend it.
Please check your pocket change. All nickels minted since mid 1938 carry a picture of Thomas Jefferson. Indian head (buffalo) nickels were minted from 1913 to early 1938.