If these are meant to be the difference of two absolute quantities, the answer is zero.
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Let the length be l, the width be w, and the area be A. The equation for the area of a rectangle is A = l*w; we know A = 77, so we need to get l in terms of w so we only have one variable to solve for. We're given l = 2w-3, so we can substitute back in: A=77=(2w-3)*w 77=2w^2-3w 0=2w^2-3w-77 0=(2w+11)*(w-7) so w=-5.5 or w=7. Since we can't have a negative width, w=7 inches. Plugging back in to our equation for l and w: l=2w-3=2(7)-3=14-3=11, so the length is 11 inches.
Area = LxW Using the figures you have 56 = L x 7 L = 56/7 L = 8
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L = 2W - 3 so W x (2W - 3) = 35, ie 2W^2 - 3W - 35 = 0 This factorises as (2W + 7)(w - 5) so the positive value for W is 5 in, making L = 7 in.