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Earn +20 ptsQ: L 7-3 l - l 3 - 7 l equals?
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The length of a rectangle is 3 less than 2 times the width If the area is 77 square inches what is the length of the rectangle?
Let the length be l, the width be w, and the area be A. The equation for the area of a rectangle is A = l*w; we know A = 77, so we need to get l in terms of w so we only have one variable to solve for. We're given l = 2w-3, so we can substitute back in: A=77=(2w-3)*w 77=2w^2-3w 0=2w^2-3w-77 0=(2w+11)*(w-7) so w=-5.5 or w=7. Since we can't have a negative width, w=7 inches. Plugging back in to our equation for l and w: l=2w-3=2(7)-3=14-3=11, so the length is 11 inches.
The area of a rectangle is 56 square inches The width of the rectangle is 7 in What is the length?
Area = LxW Using the figures you have 56 = L x 7 L = 56/7 L = 8
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The length of a rectangle is 3 inches less than twice its width if the area of the rectangle s 35 inches find the dimensions of the rectangle?
L = 2W - 3 so W x (2W - 3) = 35, ie 2W^2 - 3W - 35 = 0 This factorises as (2W + 7)(w - 5) so the positive value for W is 5 in, making L = 7 in.
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