9² = 81 square units.Area= length*length= 9*9= 81 unit square
A square with a side length of 9 units has an area of 81 square units.
A = s^2 81 in^2 = s^2 √(81 in^2) = √s^2 9 in = s Thus the side of the square is 9 inches.
A square with an area of 81 m2 has the following dimensions:Side length: 9 mPerimeter: 36 mDiagonal: 12.7 m
A square is a four sided polygon with four right angles whose sides are all congruent. This means that the area of a square is equal to the length of one side squared. So a square with an area of 81 sq. in. has a side length of 9 inches. The perimeter is the distance around the outside of a figure. For a square, this is equal to four times the side length. Here 4 * 9 = 36. So, the perimeter of this square is 36 inches.
9² = 81 square units.Area= length*length= 9*9= 81 unit square
9² = 81 square units.Area= length*length= 9*9= 81 unit square
9
The area of a square with sides of length x units is x2 square units. So x2 = 81 which implies that x = 9.
81
Area of square = x2 where x is the length of each side. So x2 = 81 sq ft x = sqrt(81) ft = 9 ft
Since the square root of 81 is 9, each side of the square would be 9 centimetres in length.
81 square meters
9 inches
To find the length of a side of a square when the area is known, you need to take the square root of the area. In this case, the area is 81 sq m, so the side length would be the square root of 81, which is 9 meters. Therefore, the side of the square is 9 meters.
The length of each of the sides is then 9 metres.
If it is a square then each side will have a length of 9 inches