their slopes are negative reciprocals of each other. and they make a right angle when they intersect.
Slopes of perpendicular lines will be opposite reciprocals. This means that the slopes have opposite signs and that one is 1/ the other. For example, 2 and -1/2.
They are negative reciprocals. So if the slope of a line is x, the slope of the perpendicular line is -1/x
3x - y = 5 is the equation of a nonvertical line. Definition: Two nonvertical lines are perpendicular if their slopes are negative reciprocals of each other. So we need to find the slope of the given line, and check which of the other lines have a slope that satisfies the definition. Solve for y. 3x - y = add y and subtract 5 to both sides 3x - 5 = y which yields the slope of 3 Thus, the line that have a slope of -1/3 is the required line.
To answer this question we need to first get the slope of the line 5x-4y=9 by rearranging it in the form of y=mx+b: 5x-4y=9 4y=5x-9 y=(5/4)x-9/4 Since the slope of parallel lines are negative reciprocals of each other, the negative reciprocal of 5/4 is -4/5, therefore the slope of a line parallel to the line 5x-4y=9 is -4/5
their slopes are negative reciprocals.
their slopes are negative reciprocals of each other. and they make a right angle when they intersect.
The slopes of perpendicular lines are reciprocals of each other. For example. if one line had an equation like y= 2x+4 then the perpendicular's slope would be y=x/2+4 -- they are reciprocals of each other.
Negative reciprocals. That is, if one line has slope m (m ≠0), then the perpendicular to it has slope -1/m. If m = 0, the slope of the perpendicular is not defined - the line is of the form x = k.
Right angles are created by perpendicular lines. You first have to find the slopes of the lines. You know lines are perpendicular when the slopes are negative reciprocals. For example: If you find the slope of Line AB to be -2, in order for the lines to form right angles, the following line would have to be 1/2. So getting back to your question, calculate the slopes and show they are negative reciprocals. Hope I Helped!
Is it possible for two lines with positive slopes to be perpendicular?
Slopes of perpendicular lines will be opposite reciprocals. This means that the slopes have opposite signs and that one is 1/ the other. For example, 2 and -1/2.
-- The slope of the graph of [ 4x + y = 2 ] is -4.-- The slopes of perpendicular lines are negative reciprocals.-- The slope of any line perpendicular to [ 4x + y = 2 ] is 1/4 .
They are the negative reciprocal of each other. Fo rexample, if a line has slope = +2, then the line perpendicular to it has slope -1/2
When two lines are perpendicular, their slopes are negative reciprocals. In the example, the perpendicular to y= (1/21) x would be y = -21 x For y = 2x, the perpendicular would be y= -½ x You invert the fraction and change the sign.
When a negative acceleration is graphed, the line slopes downward on a velocity-time graph. This is because negative acceleration causes a decrease in velocity over time, resulting in a negative slope on the graph.
They are negative reciprocals. So if the slope of a line is x, the slope of the perpendicular line is -1/x