Numbers that have 2 as a factor are those that are divisible by 2 without leaving a remainder. This includes all even numbers such as 2, 4, 6, 8, 10, and so on. In other words, any number that can be expressed as 2 multiplied by another integer is a number that has 2 as a factor.
Chat with our AI personalities
Oh, dude, you want me to list all the numbers that have 2 as a factor? Well, let me break it down for you. Basically, any even number has 2 as a factor. So, like, 2, 4, 6, 8, 10, and so on. You get the idea, right? It's like every other number, man.
Alright, sweetheart, let's keep it simple for you. Every even number has 2 as a factor. So, grab a calculator if you need to, and start counting by twos until you get tired. Just don't come crying to me when you realize there's an infinite number of them.
Well, see, that's going to be a problem, since there are an infinite number of them,
and we're a little busy just now.
But you can easily generate the list for yourself. Here's how:
-- Start at ' 1 ', and count.
-- Throw out the first number, then write down the second number.
-- Throw out a number, then write down the next number.
-- Throw out a number, then write down the next number.
-- Throw out a number, then write down the next number.
-- Throw out a number, then write down the next number.
Keep going like that. The list you write down will be a list of numbers that have ' 2 '
as a factor. You can just keep right on going for as long as you want, and make
that list as long as you want it to be.
You can also stop whenever you want to, and then you'll only have another
infinite number left to go.
256 is not prime. 256 = 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
Yes. Not counting one as a factor, you could have numbers like 6 and 10 which only share one common factor, 2.
the factor of (x^2-2) could be looked at if we write (x^2-2) as (x^2-(sqrt(2)^2 now we have the difference of squares so we can factor is... The key point here is where can your factors come from? Most often we factor over the Integers and (X^2-2) cannot be factored over the integers If we allow our field, or set of numbers over which we factor to be the real numbers, then the method I suggested works. If we allow our field to be the complex numbers then we cal always factor an expression. This is an important theorem in algebra.
Factorize the LCM 20 = 2 x 2 x 5 Factorize the HCF 300 = 2 x 2x3x5x5 The HCF is the common factor for both numbers whereas the LCM contains all the unique factors of both numbers. So, 2 x 2x5 or 20 is a common factor for both numbers. The factors remaining are 3 and 5. So, 3 is a factor of one number and 5 is the factor of the second number. The first number = 20x 3 = 60 The second number = 20x 5 = 100 So 60 and 100 are two numbers Answer = 60 and 100