Their ages: x+5+x = 39 => 2x+5 = 39 => 2x = 39-5 => 2x = 34 => x = 17
Therefore: Mary is 17+5 = 22 years and Bob is 17 years
Use variables "m" for Mary's age, and "b" for Bob's age. Then, the first statement, as an equation, is:m = b+5
And the second statement:
m+b = 39
it depends what kind it is. if you give me an example i might solve one. Joe is 10 years older than James. In 8 years, twice Joe's age will equal three times James's age. How old is each now? Answer: Joe: 3 units James: 2 units 1units=10 years 3units=30 yea
use an equation x=sue x+x+6+x+11=41 -17 -17 3x= 24 /3 /3 x= 8 sue is 8
Let L be the age of Leah, J as the age of John, and S as the age of Sue.Equation 1: S = L - 6Equation 2: J = L + 5Equation 3: L + J = 41Using Equation 3 to get Leah's age:L + J = 41L + (L + 5) = 412L = 41 - 5L = 18Using Equation 2 and substituting L to get John's age:J = L + 5J = 18 + 5J = 23Check using Equation 3, substituting L and J:L + J = 4118 + 23 = 41Using Equation 1 , substituting L to get Sue's age.S = L - 6S = 18 - 6S = 12Sue is 12 years old.Leah is 18 years old.John is 23 years old.
In 27.5 years. [By the way, I think you mean x+x+95=150.] Let x be the number of years in the future when the sum of their ages will be 150. In x years, the younger person will be 45+x and the older will be 50+x. The sum of their ages will be 150, and the equation to find x is given by: (45+x)+(50+x)=150 Now solve for x: (45+x)+(50+x)=150 95+2x=150 2x=150-95=55 x=55/2=27.5 So the sum of their ages will be 150 in 27.5 years. The younger person will be 45+27.5=72.5 and the older person will be 50+27.5=77.5.
No. Albert was about 3 years older than his sister.
Hes 10 years
You write an equation, and solve it. For example, assuming you are 20 years older than your daughter, then you will always be 20 years older: x = your daughter's age 3x = your age The statement that you are 20 years older than your daughter translates to: 3x = x + 20 If you solve this equation for "x", you'll have your daughter's age. Then you can just multiply this by 3 to have your own age. Let p = the parent's date of birth, let d = the daughter's date of birth, and let z = the date when the daughter's age is 1/3 the parent's age. z = d + (d - p) ÷ 2 z = 1.5d - 0.5p Microsoft Excel or a similar spreadsheet program is excellent for performing mathematical functions on dates.
Use a convenient variable, such as "x", for her age. Then, 3 years ago her age was x-3, in three years, her age will be x+3. Write an equation with this data:x = 3(x+3) - 3(x-3)And solve it:x = 3x + 9 - 3x + 9x = 18Use a convenient variable, such as "x", for her age. Then, 3 years ago her age was x-3, in three years, her age will be x+3. Write an equation with this data:x = 3(x+3) - 3(x-3)And solve it:x = 3x + 9 - 3x + 9x = 18Use a convenient variable, such as "x", for her age. Then, 3 years ago her age was x-3, in three years, her age will be x+3. Write an equation with this data:x = 3(x+3) - 3(x-3)And solve it:x = 3x + 9 - 3x + 9x = 18Use a convenient variable, such as "x", for her age. Then, 3 years ago her age was x-3, in three years, her age will be x+3. Write an equation with this data:x = 3(x+3) - 3(x-3)And solve it:x = 3x + 9 - 3x + 9x = 18
Write an equation for this:age + 4 = y - 5 = current_ageage = y - 5 - 4age = y - 94 years ago John was 9 years younger than he will be in 5 years when he is y years old. Sorry if this isn't much help but trying to solve an equation with 2 variables doesn't give definite numerical answers without additional information (which you did not provide).
m=2*(a+6)+2
I’m sorry this question dose not make sense please recheck the grammer
For this question we can say Nita = N and Joe = J and set up an equation:equation 1: N = J + 10 and equation 2: 20 = J + Nwe can solve for J using equation 1 inside of equation 2:20 = (J + 10) + J20 - 10 = 2*JTherefore: J = (20 - 10)/2 = 5Now we solve for N by plugging in 5 for J in equation 1:N = 5 + 10 = 15Nita is 15 and Joe is 5
Without knowing which is older, you cannot assign their ages. But one is 10 and the other is 5. The idea here is to write two equations, one for the sum of the ages (B + E = 15), one for the difference. Then, solve both equations simultaneously. There are several ways to do this; for example, you can solve one of the equations for "B", and replace that variable in the other equation. x + y = 15 x = y +5 (y+5) + y = 15 2y + 5 = 15 2y = 10 y = 5 (the younger child), x = y+5 = 10 (the older child).
Pete the pilot is 35 years old. His son is 9 years old. In how many years will Pete be exactly three times older than his son
growing older
The father is always 28 years older than his son so the equation can be written: (1) father = son + 28 at all times after birth at some point father is three times older than son so: (2) father = 3son So we can combine (1) and (2) equations as: 3son = son + 28 2son = 28 son = 14 so when the son is 14 the father is 28 years older which is 42 and 3 times older than 14.
The amount of material left in radioactive decay is an exponential function. Therefore, the way you solve this is to write it as an exponential function; for example: f = e-kt, where "f" is the fraction remaining after a certain time, "t" is the time in any unit you choose (for example, years), and "k" is a constant you have to find out. Replace the numbers you know (for t = 1600 years, f = 1/2, since 1/2 of the original remains), and solve for "k". Then, write the equation again, this time with the constant "k" you figured out before, and the time (365 years). This will give you the fraction left after that amount of time.