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Their ages: x+5+x = 39 => 2x+5 = 39 => 2x = 39-5 => 2x = 34 => x = 17
Therefore: Mary is 17+5 = 22 years and Bob is 17 years

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7y ago
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7y ago

Use variables "m" for Mary's age, and "b" for Bob's age. Then, the first statement, as an equation, is:m = b+5

And the second statement:

m+b = 39

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Q: Mary is 5 years older than bob. If the sum of their ages is 39 write and solve an equation to find ages?
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What can you do to solve hard algebra problems?

it depends what kind it is. if you give me an example i might solve one. Joe is 10 years older than James. In 8 years, twice Joe's age will equal three times James's age. How old is each now? Answer: Joe: 3 units James: 2 units 1units=10 years 3units=30 yea


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If Leah is 6 years older than Sue and John is 5 years older Leah and the total of their ages is 41 how old is Sue?

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When will two persons aged 45 and 50 equal 150 using this equation X plus x plus 5 equals 150?

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