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If a number is divisible by 5, it either ends in a 0 or a 5. Since this doesn't end in either, we know it isn't divisible by 5. We should find the next lowest number that is divisible by 5. Since 155 ends in a five, we know it is divisible by 5, and because this is the closest number below 157 that is divisible by 155, we know this is the greatest number of students that could be put equally into 5 classes.
Alternatively, we can divide 157 by 5, and we get 31.4. Since we only want something that divides evenly by 5, we round this down to 31, then multiply by 5 to get 155.
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A school has 18 classes with 35 students in order to reduce class size to 30 how many classes must be formed?
18 * 35 = 630 total students 630 / 30 = 21 total classes An additional 3 classes.
A school has 18 classes with 35 students in each class. in order to reduce class size to 30how many new classes need to be formed?
A school has 18 classes with 35 students in each class. In order to reduce class size to 30, how many new classes must be formed?
Mr Joness algebra class has too many students in it If the class were split exactly in equal parts to form 3 new classes each class would have no more than 14 students in it?
Any number up to & including 14 in the new classes
Mr Jones's algebra class has too many students in it If the class were split exactly in equal parts to form 3 new classes each class would have no more than 14 students in it?
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Mr Jones algebra class has too many students in it If the class were split exactly in half to form 2 new classes each class would have no more than 17 students in it?
17>=(s/2)
